Base | Representation |
---|---|
bin | 111000111000011000… |
… | …1000111011100101001 |
3 | 102200021220200010210221 |
4 | 1301300301013130221 |
5 | 4000131124224131 |
6 | 132040532010041 |
7 | 11553005302606 |
oct | 1616061073451 |
9 | 380256603727 |
10 | 122151008041 |
11 | 47893072317 |
12 | 1b810160921 |
13 | b698a243aa |
14 | 5caacad6ad |
15 | 329dc46411 |
hex | 1c70c47729 |
122151008041 has 2 divisors, whose sum is σ = 122151008042. Its totient is φ = 122151008040.
The previous prime is 122151007931. The next prime is 122151008099. The reversal of 122151008041 is 140800151221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 63103952025 + 59047056016 = 251205^2 + 242996^2 .
It is a cyclic number.
It is not a de Polignac number, because 122151008041 - 211 = 122151005993 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 122151007997 and 122151008015.
It is not a weakly prime, because it can be changed into another prime (122151908041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61075504020 + 61075504021.
It is an arithmetic number, because the mean of its divisors is an integer number (61075504021).
Almost surely, 2122151008041 is an apocalyptic number.
It is an amenable number.
122151008041 is a deficient number, since it is larger than the sum of its proper divisors (1).
122151008041 is an equidigital number, since it uses as much as digits as its factorization.
122151008041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 640, while the sum is 25.
Adding to 122151008041 its reverse (140800151221), we get a palindrome (262951159262).
The spelling of 122151008041 in words is "one hundred twenty-two billion, one hundred fifty-one million, eight thousand, forty-one".
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