Base | Representation |
---|---|
bin | 1011000111000100010111… |
… | …0000101000100110011111 |
3 | 1121020211210001010112202001 |
4 | 2301301011300220212133 |
5 | 3100121441141220233 |
6 | 41551551305143131 |
7 | 2400403201226263 |
oct | 261610560504637 |
9 | 47224701115661 |
10 | 12216057366943 |
11 | 398a889a034a1 |
12 | 1453678a8aaa7 |
13 | 6a7c7a62c601 |
14 | 3033904c60a3 |
15 | 162b7ae1d27d |
hex | b1c45c2899f |
12216057366943 has 2 divisors, whose sum is σ = 12216057366944. Its totient is φ = 12216057366942.
The previous prime is 12216057366911. The next prime is 12216057367103. The reversal of 12216057366943 is 34966375061221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12216057366943 - 25 = 12216057366911 is a prime.
It is a super-3 number, since 3×122160573669433 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12216057364943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6108028683471 + 6108028683472.
It is an arithmetic number, because the mean of its divisors is an integer number (6108028683472).
Almost surely, 212216057366943 is an apocalyptic number.
12216057366943 is a deficient number, since it is larger than the sum of its proper divisors (1).
12216057366943 is an equidigital number, since it uses as much as digits as its factorization.
12216057366943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9797760, while the sum is 55.
The spelling of 12216057366943 in words is "twelve trillion, two hundred sixteen billion, fifty-seven million, three hundred sixty-six thousand, nine hundred forty-three".
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