Base | Representation |
---|---|
bin | 10110110000101111… |
… | …01001101001011011 |
3 | 1011112122002222122112 |
4 | 23120113221221123 |
5 | 200011310410042 |
6 | 5340325142535 |
7 | 611552253326 |
oct | 133027515133 |
9 | 34478088575 |
10 | 12220013147 |
11 | 5200973821 |
12 | 245055aa4b |
13 | 11c9908214 |
14 | 83cd2d7bd |
15 | 4b7c2e982 |
hex | 2d85e9a5b |
12220013147 has 2 divisors, whose sum is σ = 12220013148. Its totient is φ = 12220013146.
The previous prime is 12220013123. The next prime is 12220013161. The reversal of 12220013147 is 74131002221.
It is a strong prime.
It is an emirp because it is prime and its reverse (74131002221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12220013147 - 218 = 12219751003 is a prime.
It is not a weakly prime, because it can be changed into another prime (12220013107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110006573 + 6110006574.
It is an arithmetic number, because the mean of its divisors is an integer number (6110006574).
Almost surely, 212220013147 is an apocalyptic number.
12220013147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12220013147 is an equidigital number, since it uses as much as digits as its factorization.
12220013147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 672, while the sum is 23.
Adding to 12220013147 its reverse (74131002221), we get a palindrome (86351015368).
The spelling of 12220013147 in words is "twelve billion, two hundred twenty million, thirteen thousand, one hundred forty-seven".
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