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1222002103113 = 321112343455587
BaseRepresentation
bin10001110010000101000…
…000000101001101001001
311022211012102112202101100
4101302011000011031021
5130010130014244423
62333214030012013
7154200231331161
oct21620500051511
94284172482340
101222002103113
11431280369890
121789ba047009
138b3079c502c
14432066955a1
1521bc15d2343
hex11c85005349

1222002103113 has 12 divisors (see below), whose sum is σ = 1925579071728. Its totient is φ = 740607335160.

The previous prime is 1222002103093. The next prime is 1222002103151. The reversal of 1222002103113 is 3113012002221.

1222002103113 is a `hidden beast` number, since 122 + 20 + 0 + 210 + 311 + 3 = 666.

It is not a de Polignac number, because 1222002103113 - 229 = 1221465232201 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1222002103183) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6171727695 + ... + 6171727892.

It is an arithmetic number, because the mean of its divisors is an integer number (160464922644).

Almost surely, 21222002103113 is an apocalyptic number.

It is an amenable number.

1222002103113 is a deficient number, since it is larger than the sum of its proper divisors (703576968615).

1222002103113 is a wasteful number, since it uses less digits than its factorization.

1222002103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12343455604 (or 12343455601 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 1222002103113 its reverse (3113012002221), we get a palindrome (4335014105334).

The spelling of 1222002103113 in words is "one trillion, two hundred twenty-two billion, two million, one hundred three thousand, one hundred thirteen".

Divisors: 1 3 9 11 33 99 12343455587 37030366761 111091100283 135778011457 407334034371 1222002103113