Base | Representation |
---|---|
bin | 10001110010000101100… |
… | …010000001010110000001 |
3 | 11022211020001021202212211 |
4 | 101302011202001112001 |
5 | 130010134304001233 |
6 | 2333214544422121 |
7 | 154200400055164 |
oct | 21620542012601 |
9 | 4284201252784 |
10 | 1222011000193 |
11 | 431285396345 |
12 | 178a01017941 |
13 | 8b3097bb889 |
14 | 4320792dadb |
15 | 21bc228d5cd |
hex | 11c85881581 |
1222011000193 has 2 divisors, whose sum is σ = 1222011000194. Its totient is φ = 1222011000192.
The previous prime is 1222011000157. The next prime is 1222011000229. The reversal of 1222011000193 is 3910001102221.
It is a balanced prime because it is at equal distance from previous prime (1222011000157) and next prime (1222011000229).
It can be written as a sum of positive squares in only one way, i.e., 1133187927169 + 88823073024 = 1064513^2 + 298032^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1222011000193 is a prime.
It is not a weakly prime, because it can be changed into another prime (1222011000893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611005500096 + 611005500097.
It is an arithmetic number, because the mean of its divisors is an integer number (611005500097).
Almost surely, 21222011000193 is an apocalyptic number.
It is an amenable number.
1222011000193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1222011000193 is an equidigital number, since it uses as much as digits as its factorization.
1222011000193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 22.
The spelling of 1222011000193 in words is "one trillion, two hundred twenty-two billion, eleven million, one hundred ninety-three", and thus it is an aban number.
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