Base | Representation |
---|---|
bin | 111000111001111000… |
… | …1000000101110000011 |
3 | 102200102102022212001101 |
4 | 1301303301000232003 |
5 | 4000232013442011 |
6 | 132045530115231 |
7 | 11554156005013 |
oct | 1616361005603 |
9 | 380372285041 |
10 | 122201312131 |
11 | 47909500548 |
12 | 1b824b7bb17 |
13 | b6a6288022 |
14 | 5cb3845c43 |
15 | 32a33812c1 |
hex | 1c73c40b83 |
122201312131 has 2 divisors, whose sum is σ = 122201312132. Its totient is φ = 122201312130.
The previous prime is 122201312117. The next prime is 122201312137. The reversal of 122201312131 is 131213102221.
It is a strong prime.
It is an emirp because it is prime and its reverse (131213102221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122201312131 - 211 = 122201310083 is a prime.
It is a super-2 number, since 2×1222013121312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 122201312099 and 122201312108.
It is not a weakly prime, because it can be changed into another prime (122201312137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61100656065 + 61100656066.
It is an arithmetic number, because the mean of its divisors is an integer number (61100656066).
Almost surely, 2122201312131 is an apocalyptic number.
122201312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
122201312131 is an equidigital number, since it uses as much as digits as its factorization.
122201312131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 122201312131 its reverse (131213102221), we get a palindrome (253414414352).
The spelling of 122201312131 in words is "one hundred twenty-two billion, two hundred one million, three hundred twelve thousand, one hundred thirty-one".
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