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122202312316037 is a prime number
BaseRepresentation
bin11011110010010001110001…
…011010101001010010000101
3121000200102112020221101200122
4123302101301122221102011
5112004130313423103122
61111522544532551325
734511553135044342
oct3362216132512205
9530612466841618
10122202312316037
1135a34789549488
1211857763182545
135325823078145
1422268a2b577c9
15e1db68aad142
hex6f24716a9485

122202312316037 has 2 divisors, whose sum is σ = 122202312316038. Its totient is φ = 122202312316036.

The previous prime is 122202312316033. The next prime is 122202312316067. The reversal of 122202312316037 is 730613213202221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120713312015521 + 1489000300516 = 10986961^2 + 1220246^2 .

It is a cyclic number.

It is not a de Polignac number, because 122202312316037 - 22 = 122202312316033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 122202312315988 and 122202312316006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122202312316033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61101156158018 + 61101156158019.

It is an arithmetic number, because the mean of its divisors is an integer number (61101156158019).

Almost surely, 2122202312316037 is an apocalyptic number.

It is an amenable number.

122202312316037 is a deficient number, since it is larger than the sum of its proper divisors (1).

122202312316037 is an equidigital number, since it uses as much as digits as its factorization.

122202312316037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288, while the sum is 35.

Adding to 122202312316037 its reverse (730613213202221), we get a palindrome (852815525518258).

The spelling of 122202312316037 in words is "one hundred twenty-two trillion, two hundred two billion, three hundred twelve million, three hundred sixteen thousand, thirty-seven".