Base | Representation |
---|---|
bin | 1011000111010110110001… |
… | …0111010010011001011001 |
3 | 1121021022112111120101011212 |
4 | 2301311230113102121121 |
5 | 3100212102000013423 |
6 | 41554125551032505 |
7 | 2400636526020401 |
oct | 261655427223131 |
9 | 47238474511155 |
10 | 12221000001113 |
11 | 3991995999722 |
12 | 145461820b735 |
13 | 6a8587624207 |
14 | 3036dcad3801 |
15 | 162d69ce2578 |
hex | b1d6c5d2659 |
12221000001113 has 2 divisors, whose sum is σ = 12221000001114. Its totient is φ = 12221000001112.
The previous prime is 12221000001079. The next prime is 12221000001157. The reversal of 12221000001113 is 31110000012221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6200513346889 + 6020486654224 = 2490083^2 + 2453668^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12221000001113 is a prime.
It is not a weakly prime, because it can be changed into another prime (12221000001193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110500000556 + 6110500000557.
It is an arithmetic number, because the mean of its divisors is an integer number (6110500000557).
Almost surely, 212221000001113 is an apocalyptic number.
It is an amenable number.
12221000001113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221000001113 is an equidigital number, since it uses as much as digits as its factorization.
12221000001113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 12221000001113 its reverse (31110000012221), we get a palindrome (43331000013334).
The spelling of 12221000001113 in words is "twelve trillion, two hundred twenty-one billion, one thousand, one hundred thirteen".
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