Base | Representation |
---|---|
bin | 10110110000110111… |
… | …10011000101110001 |
3 | 1011112201011020002012 |
4 | 23120123303011301 |
5 | 200012100203101 |
6 | 5340404332305 |
7 | 611564432216 |
oct | 133033630561 |
9 | 34481136065 |
10 | 12221100401 |
11 | 5201546684 |
12 | 24509a4095 |
13 | 11c9bc9073 |
14 | 83d133b0d |
15 | 4b7d96bbb |
hex | 2d86f3171 |
12221100401 has 2 divisors, whose sum is σ = 12221100402. Its totient is φ = 12221100400.
The previous prime is 12221100373. The next prime is 12221100413. The reversal of 12221100401 is 10400112221.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8836188001 + 3384912400 = 94001^2 + 58180^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12221100401 is a prime.
It is a super-2 number, since 2×122211004012 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (12221100421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110550200 + 6110550201.
It is an arithmetic number, because the mean of its divisors is an integer number (6110550201).
Almost surely, 212221100401 is an apocalyptic number.
It is an amenable number.
12221100401 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221100401 is an equidigital number, since it uses as much as digits as its factorization.
12221100401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 12221100401 its reverse (10400112221), we get a palindrome (22621212622).
The spelling of 12221100401 in words is "twelve billion, two hundred twenty-one million, one hundred thousand, four hundred one".
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