Base | Representation |
---|---|
bin | 11011110010011011101110… |
… | …100101000110000101110111 |
3 | 121000201110010020201211020101 |
4 | 123302123232211012011313 |
5 | 112004314212022021241 |
6 | 1111531513401014531 |
7 | 34512412060055041 |
oct | 3362335645060567 |
9 | 530643106654211 |
10 | 122213002142071 |
11 | 35a39274693a55 |
12 | 11859847184447 |
13 | 5326837951ba9 |
14 | 22271d8766a91 |
15 | e1e0922cde31 |
hex | 6f26ee946177 |
122213002142071 has 2 divisors, whose sum is σ = 122213002142072. Its totient is φ = 122213002142070.
The previous prime is 122213002142057. The next prime is 122213002142131. The reversal of 122213002142071 is 170241200312221.
It is a weak prime.
It is an emirp because it is prime and its reverse (170241200312221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122213002142071 - 225 = 122212968587639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122213002140071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61106501071035 + 61106501071036.
It is an arithmetic number, because the mean of its divisors is an integer number (61106501071036).
Almost surely, 2122213002142071 is an apocalyptic number.
122213002142071 is a deficient number, since it is larger than the sum of its proper divisors (1).
122213002142071 is an equidigital number, since it uses as much as digits as its factorization.
122213002142071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 122213002142071 its reverse (170241200312221), we get a palindrome (292454202454292).
The spelling of 122213002142071 in words is "one hundred twenty-two trillion, two hundred thirteen billion, two million, one hundred forty-two thousand, seventy-one".
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