Base | Representation |
---|---|
bin | 10001110010001100110… |
… | …011111010101101000101 |
3 | 11022211112120002201100211 |
4 | 101302030303322231011 |
5 | 130010412040211401 |
6 | 2333235030235421 |
7 | 154203412135660 |
oct | 21621463725505 |
9 | 4284476081324 |
10 | 1222133132101 |
11 | 431338323902 |
12 | 178a35ab5b71 |
13 | 8b328bb0c8b |
14 | 43219c426d7 |
15 | 21bccd65951 |
hex | 11c8ccfab45 |
1222133132101 has 4 divisors (see below), whose sum is σ = 1396723579552. Its totient is φ = 1047542684652.
The previous prime is 1222133132083. The next prime is 1222133132123. The reversal of 1222133132101 is 1012313312221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1222133132101 - 215 = 1222133099333 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1222133132201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87295223715 + ... + 87295223728.
It is an arithmetic number, because the mean of its divisors is an integer number (349180894888).
Almost surely, 21222133132101 is an apocalyptic number.
It is an amenable number.
1222133132101 is a deficient number, since it is larger than the sum of its proper divisors (174590447451).
1222133132101 is an equidigital number, since it uses as much as digits as its factorization.
1222133132101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 174590447450.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1222133132101 its reverse (1012313312221), we get a palindrome (2234446444322).
The spelling of 1222133132101 in words is "one trillion, two hundred twenty-two billion, one hundred thirty-three million, one hundred thirty-two thousand, one hundred one".
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