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12222004433 is a prime number
BaseRepresentation
bin10110110000111110…
…01111110011010001
31011112202212011011212
423120133033303101
5200012313120213
65340435545505
7611605215662
oct133037176321
934482764155
1012222004433
115202003911
12245115b295
1311ca1546b2
1483d2cb369
154b7ec49a8
hex2d87cfcd1

12222004433 has 2 divisors, whose sum is σ = 12222004434. Its totient is φ = 12222004432.

The previous prime is 12222004387. The next prime is 12222004517. The reversal of 12222004433 is 33440022221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12212902144 + 9102289 = 110512^2 + 3017^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12222004433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12222004399 and 12222004408.

It is not a weakly prime, because it can be changed into another prime (12222000433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111002216 + 6111002217.

It is an arithmetic number, because the mean of its divisors is an integer number (6111002217).

Almost surely, 212222004433 is an apocalyptic number.

It is an amenable number.

12222004433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12222004433 is an equidigital number, since it uses as much as digits as its factorization.

12222004433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 23.

Adding to 12222004433 its reverse (33440022221), we get a palindrome (45662026654).

The spelling of 12222004433 in words is "twelve billion, two hundred twenty-two million, four thousand, four hundred thirty-three".