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12222156893 is a prime number
BaseRepresentation
bin10110110000111111…
…10101000001011101
31011112210010220022112
423120133311001131
5200012333010033
65340443123405
7611606422322
oct133037650135
934483126275
1012222156893
1152020a8411
122451213565
1311ca1a8bcb
1483d32ab49
154b8004c48
hex2d87f505d

12222156893 has 2 divisors, whose sum is σ = 12222156894. Its totient is φ = 12222156892.

The previous prime is 12222156889. The next prime is 12222156941. The reversal of 12222156893 is 39865122221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12082846084 + 139310809 = 109922^2 + 11803^2 .

It is an emirp because it is prime and its reverse (39865122221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12222156893 - 22 = 12222156889 is a prime.

It is a super-2 number, since 2×122221568932 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12222156893.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12222156883) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111078446 + 6111078447.

It is an arithmetic number, because the mean of its divisors is an integer number (6111078447).

Almost surely, 212222156893 is an apocalyptic number.

It is an amenable number.

12222156893 is a deficient number, since it is larger than the sum of its proper divisors (1).

12222156893 is an equidigital number, since it uses as much as digits as its factorization.

12222156893 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 103680, while the sum is 41.

The spelling of 12222156893 in words is "twelve billion, two hundred twenty-two million, one hundred fifty-six thousand, eight hundred ninety-three".