Base | Representation |
---|---|
bin | 10110110001000000… |
… | …00011000100100001 |
3 | 1011112210020211020122 |
4 | 23120200003010201 |
5 | 200012341330213 |
6 | 5340444250025 |
7 | 611610052142 |
oct | 133040030441 |
9 | 34483224218 |
10 | 12222214433 |
11 | 5202137670 |
12 | 2451240915 |
13 | 11ca1c9160 |
14 | 83d343ac9 |
15 | 4b8016d08 |
hex | 2d8803121 |
12222214433 has 16 divisors (see below), whose sum is σ = 14372309952. Its totient is φ = 10246872000.
The previous prime is 12222214429. The next prime is 12222214439. The reversal of 12222214433 is 33441222221.
It is a cyclic number.
It is not a de Polignac number, because 12222214433 - 22 = 12222214429 is a prime.
It is a super-2 number, since 2×122222144332 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12222214439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 116843 + ... + 195183.
It is an arithmetic number, because the mean of its divisors is an integer number (898269372).
Almost surely, 212222214433 is an apocalyptic number.
12222214433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12222214433 is a deficient number, since it is larger than the sum of its proper divisors (2150095519).
12222214433 is a wasteful number, since it uses less digits than its factorization.
12222214433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79456.
The product of its digits is 4608, while the sum is 26.
Adding to 12222214433 its reverse (33441222221), we get a palindrome (45663436654).
The spelling of 12222214433 in words is "twelve billion, two hundred twenty-two million, two hundred fourteen thousand, four hundred thirty-three".
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