Base | Representation |
---|---|
bin | 11011110010100100010100… |
… | …000000011011101100000001 |
3 | 121000202022220122202112010221 |
4 | 123302210110000123230001 |
5 | 112004442101310000001 |
6 | 1111540040203423041 |
7 | 34513156356421312 |
oct | 3362442400335401 |
9 | 530668818675127 |
10 | 122222220000001 |
11 | 35a42174955060 |
12 | 1185b59a224a81 |
13 | 532767659c8b4 |
14 | 2227830a8c609 |
15 | e1e4316911a1 |
hex | 6f291401bb01 |
122222220000001 has 4 divisors (see below), whose sum is σ = 133333330909104. Its totient is φ = 111111109090900.
The previous prime is 122222219999983. The next prime is 122222220000017. The reversal of 122222220000001 is 100000022222221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 122222220000001 - 217 = 122222219868929 is a prime.
It is a super-5 number, since 5×1222222200000015 (a number of 72 digits) contains 55555 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 122222220000001.
It is not an unprimeable number, because it can be changed into a prime (122222220001001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5555555454535 + ... + 5555555454556.
It is an arithmetic number, because the mean of its divisors is an integer number (33333332727276).
Almost surely, 2122222220000001 is an apocalyptic number.
122222220000001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
122222220000001 is a deficient number, since it is larger than the sum of its proper divisors (11111110909103).
122222220000001 is a wasteful number, since it uses less digits than its factorization.
122222220000001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11111110909102.
The product of its (nonzero) digits is 128, while the sum is 16.
Adding to 122222220000001 its reverse (100000022222221), we get a palindrome (222222242222222).
The spelling of 122222220000001 in words is "one hundred twenty-two trillion, two hundred twenty-two billion, two hundred twenty million, one", and thus it is an aban number.
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