Base | Representation |
---|---|
bin | 1011000111011011100111… |
… | …1111001100111100000111 |
3 | 1121021102220021002112022221 |
4 | 2301312321333030330013 |
5 | 3100222233342411101 |
6 | 41554503112033211 |
7 | 2401014021325633 |
oct | 261667177147407 |
9 | 47242807075287 |
10 | 12222302310151 |
11 | 39924a402378a |
12 | 1454920392807 |
13 | 6a873438a18b |
14 | 3037c3a55dc3 |
15 | 162de42dbaa1 |
hex | b1db9fccf07 |
12222302310151 has 2 divisors, whose sum is σ = 12222302310152. Its totient is φ = 12222302310150.
The previous prime is 12222302310091. The next prime is 12222302310263. The reversal of 12222302310151 is 15101320322221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12222302310151 - 213 = 12222302301959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12222302310451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111151155075 + 6111151155076.
It is an arithmetic number, because the mean of its divisors is an integer number (6111151155076).
Almost surely, 212222302310151 is an apocalyptic number.
12222302310151 is a deficient number, since it is larger than the sum of its proper divisors (1).
12222302310151 is an equidigital number, since it uses as much as digits as its factorization.
12222302310151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 12222302310151 its reverse (15101320322221), we get a palindrome (27323622632372).
The spelling of 12222302310151 in words is "twelve trillion, two hundred twenty-two billion, three hundred two million, three hundred ten thousand, one hundred fifty-one".
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