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122230113132 = 22314097229129
BaseRepresentation
bin111000111010101111…
…0111000001101101100
3102200111102112002121010
41301311132320031230
54000311402110012
6132052435305220
711554655550651
oct1616536701554
9380442462533
10122230113132
1147923792126
121b83274b210
13b6ac23033a
145cb75c1c28
1532a5b6ec3c
hex1c757b836c

122230113132 has 24 divisors (see below), whose sum is σ = 285406052400. Its totient is φ = 40714448896.

The previous prime is 122230113079. The next prime is 122230113143. The reversal of 122230113132 is 231311032221.

It is a junction number, because it is equal to n+sod(n) for n = 122230113099 and 122230113108.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3597657 + ... + 3631472.

It is an arithmetic number, because the mean of its divisors is an integer number (11891918850).

Almost surely, 2122230113132 is an apocalyptic number.

122230113132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

122230113132 is an abundant number, since it is smaller than the sum of its proper divisors (163175939268).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

122230113132 is a wasteful number, since it uses less digits than its factorization.

122230113132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7230545 (or 7230543 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 122230113132 its reverse (231311032221), we get a palindrome (353541145353).

The spelling of 122230113132 in words is "one hundred twenty-two billion, two hundred thirty million, one hundred thirteen thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 1409 2818 4227 5636 8454 16908 7229129 14458258 21687387 28916516 43374774 86749548 10185842761 20371685522 30557528283 40743371044 61115056566 122230113132