Base | Representation |
---|---|
bin | 1011000111011110010011… |
… | …0101101010110001101011 |
3 | 1121021111202100212111121212 |
4 | 2301313210311222301223 |
5 | 3100230221413344321 |
6 | 41555102313023335 |
7 | 2401040601133460 |
oct | 261674465526153 |
9 | 47244670774555 |
10 | 12223021231211 |
11 | 399283291681a |
12 | 1454aa10b4b4b |
13 | 6a881a2c285b |
14 | 303851317667 |
15 | 162e3749a55b |
hex | b1de4d6ac6b |
12223021231211 has 4 divisors (see below), whose sum is σ = 13969167121392. Its totient is φ = 10476875341032.
The previous prime is 12223021231189. The next prime is 12223021231241. The reversal of 12223021231211 is 11213212032221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12223021231211 - 218 = 12223020969067 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12223021231241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 873072945080 + ... + 873072945093.
It is an arithmetic number, because the mean of its divisors is an integer number (3492291780348).
Almost surely, 212223021231211 is an apocalyptic number.
12223021231211 is a deficient number, since it is larger than the sum of its proper divisors (1746145890181).
12223021231211 is an equidigital number, since it uses as much as digits as its factorization.
12223021231211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1746145890180.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 12223021231211 its reverse (11213212032221), we get a palindrome (23436233263432).
The spelling of 12223021231211 in words is "twelve trillion, two hundred twenty-three billion, twenty-one million, two hundred thirty-one thousand, two hundred eleven".
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