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12223334456813 is a prime number
BaseRepresentation
bin1011000111011111011110…
…0000100001110111101101
31121021112120012021000101002
42301313313200201313231
53100231342110104223
641555153342330045
72401051423405604
oct261676740416755
947245505230332
1012223334456813
113992983703857
121454b69b89925
136a886a17144c
14303880b70a3b
15162e54c1ce28
hexb1df7821ded

12223334456813 has 2 divisors, whose sum is σ = 12223334456814. Its totient is φ = 12223334456812.

The previous prime is 12223334456747. The next prime is 12223334456821. The reversal of 12223334456813 is 31865443332221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6780618097444 + 5442716359369 = 2603962^2 + 2332963^2 .

It is an emirp because it is prime and its reverse (31865443332221) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12223334456813 is a prime.

It is a super-2 number, since 2×122233344568132 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12223334456843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111667228406 + 6111667228407.

It is an arithmetic number, because the mean of its divisors is an integer number (6111667228407).

Almost surely, 212223334456813 is an apocalyptic number.

It is an amenable number.

12223334456813 is a deficient number, since it is larger than the sum of its proper divisors (1).

12223334456813 is an equidigital number, since it uses as much as digits as its factorization.

12223334456813 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2488320, while the sum is 47.

The spelling of 12223334456813 in words is "twelve trillion, two hundred twenty-three billion, three hundred thirty-four million, four hundred fifty-six thousand, eight hundred thirteen".