Base | Representation |
---|---|
bin | 10110110001001101… |
… | …11111010101010101 |
3 | 1011112220200021101221 |
4 | 23120212333111111 |
5 | 200013323043013 |
6 | 5340551250341 |
7 | 611631401323 |
oct | 133046772525 |
9 | 34486607357 |
10 | 12224034133 |
11 | 520316a853 |
12 | 24519799b1 |
13 | 11ca6b54bc |
14 | 83d698d13 |
15 | 4b827608d |
hex | 2d89bf555 |
12224034133 has 4 divisors (see below), whose sum is σ = 12224444128. Its totient is φ = 12223624140.
The previous prime is 12224034083. The next prime is 12224034139. The reversal of 12224034133 is 33143042221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12224034133 - 213 = 12224025941 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12224034098 and 12224034107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12224034139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156441 + ... + 221182.
It is an arithmetic number, because the mean of its divisors is an integer number (3056111032).
Almost surely, 212224034133 is an apocalyptic number.
It is an amenable number.
12224034133 is a deficient number, since it is larger than the sum of its proper divisors (409995).
12224034133 is an equidigital number, since it uses as much as digits as its factorization.
12224034133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 409994.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 12224034133 its reverse (33143042221), we get a palindrome (45367076354).
The spelling of 12224034133 in words is "twelve billion, two hundred twenty-four million, thirty-four thousand, one hundred thirty-three".
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