Base | Representation |
---|---|
bin | 1011000111111000011100… |
… | …1101101110100010000111 |
3 | 1121022011212112200221201111 |
4 | 2301332013031232202013 |
5 | 3100334110321224333 |
6 | 42002223014305451 |
7 | 2401406542200313 |
oct | 261760715564207 |
9 | 47264775627644 |
10 | 12230040414343 |
11 | 3995804a82a14 |
12 | 145631b958287 |
13 | 6a939858415b |
14 | 303d19628b43 |
15 | 1631e88034cd |
hex | b1f8736e887 |
12230040414343 has 8 divisors (see below), whose sum is σ = 12901896841520. Its totient is φ = 11561000996160.
The previous prime is 12230040414337. The next prime is 12230040414379. The reversal of 12230040414343 is 34341404003221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-12230040414343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12230040414443) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 704243328 + ... + 704260693.
It is an arithmetic number, because the mean of its divisors is an integer number (1612737105190).
Almost surely, 212230040414343 is an apocalyptic number.
12230040414343 is a deficient number, since it is larger than the sum of its proper divisors (671856427177).
12230040414343 is a wasteful number, since it uses less digits than its factorization.
12230040414343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1408504497.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 12230040414343 its reverse (34341404003221), we get a palindrome (46571444417564).
The spelling of 12230040414343 in words is "twelve trillion, two hundred thirty billion, forty million, four hundred fourteen thousand, three hundred forty-three".
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