1223014404031 has 4 divisors (see below), whose sum is σ = 1397730747472. Its totient is φ = 1048298060592.

The previous prime is 1223014404011. The next prime is 1223014404067. The reversal of 1223014404031 is 1304044103221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1223014404031 - 2¹³ = 1223014395839 is a prime.

It is a super-2 number, since 2×1223014404031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1223014403987 and 1223014404005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1223014404011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87358171710 + ... + 87358171723.

It is an arithmetic number, because the mean of its divisors is an integer number (349432686868).

Almost surely, 2^{1223014404031} is an apocalyptic number.

1223014404031 is a deficient number, since it is larger than the sum of its proper divisors (174716343441).

1223014404031 is an equidigital number, since it uses as much as digits as its factorization.

1223014404031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 174716343440.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1223014404031 its reverse (1304044103221), we get a palindrome (2527058507252).

The spelling of 1223014404031 in words is "one trillion, two hundred twenty-three billion, fourteen million, four hundred four thousand, thirty-one".