Base | Representation |
---|---|
bin | 11011110011101110100111… |
… | …111011110100011110100001 |
3 | 121001000221212110000222200211 |
4 | 123303232213323310132201 |
5 | 112012244004333330423 |
6 | 1112040433542414121 |
7 | 34522012564611331 |
oct | 3363564773643641 |
9 | 531027773028624 |
10 | 122302011230113 |
11 | 35a72a9aa29240 |
12 | 11872b48131341 |
13 | 5332051399720 |
14 | 222b63dc010c1 |
15 | e2155167210d |
hex | 6f3ba7ef47a1 |
122302011230113 has 32 divisors (see below), whose sum is σ = 143982048228480. Its totient is φ = 102417927413760.
The previous prime is 122302011230039. The next prime is 122302011230159. The reversal of 122302011230113 is 311032110203221.
It is a cyclic number.
It is not a de Polignac number, because 122302011230113 - 217 = 122302011099041 is a prime.
It is not an unprimeable number, because it can be changed into a prime (122302011230173) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 225446431 + ... + 225988267.
It is an arithmetic number, because the mean of its divisors is an integer number (4499439007140).
Almost surely, 2122302011230113 is an apocalyptic number.
122302011230113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
122302011230113 is a deficient number, since it is larger than the sum of its proper divisors (21680036998367).
122302011230113 is a wasteful number, since it uses less digits than its factorization.
122302011230113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 545137.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 122302011230113 its reverse (311032110203221), we get a palindrome (433334121433334).
The spelling of 122302011230113 in words is "one hundred twenty-two trillion, three hundred two billion, eleven million, two hundred thirty thousand, one hundred thirteen".
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