Base | Representation |
---|---|
bin | 1011000111111001000011… |
… | …0111101001111010010011 |
3 | 1121022012021211111200211012 |
4 | 2301332100313221322103 |
5 | 3100334423303303103 |
6 | 42002251042241135 |
7 | 2401413550101011 |
oct | 261762067517223 |
9 | 47265254450735 |
10 | 12230202400403 |
11 | 3995888461499 |
12 | 14563660561ab |
13 | 6a93c2cbb8b0 |
14 | 303d32d538b1 |
15 | 163207b4e2d8 |
hex | b1f90de9e93 |
12230202400403 has 16 divisors (see below), whose sum is σ = 13459850127360. Its totient is φ = 11042128991136.
The previous prime is 12230202400393. The next prime is 12230202400441. The reversal of 12230202400403 is 30400420203221.
It is a cyclic number.
It is not a de Polignac number, because 12230202400403 - 210 = 12230202399379 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12230202400463) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5467175 + ... + 7372272.
It is an arithmetic number, because the mean of its divisors is an integer number (841240632960).
Almost surely, 212230202400403 is an apocalyptic number.
12230202400403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12230202400403 is a deficient number, since it is larger than the sum of its proper divisors (1229647726957).
12230202400403 is a wasteful number, since it uses less digits than its factorization.
12230202400403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12841066.
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 12230202400403 its reverse (30400420203221), we get a palindrome (42630622603624).
The spelling of 12230202400403 in words is "twelve trillion, two hundred thirty billion, two hundred two million, four hundred thousand, four hundred three".
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