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122303101433 is a prime number
BaseRepresentation
bin111000111100111010…
…1010011100111111001
3102200200111212021201112
41301321311103213321
54000434043221213
6132104003530105
711556533131562
oct1617165234771
9380614767645
10122303101433
1147960a04337
121b853089935
13b6c13a7096
145cc3181169
1532ac28aea8
hex1c79d539f9

122303101433 has 2 divisors, whose sum is σ = 122303101434. Its totient is φ = 122303101432.

The previous prime is 122303101421. The next prime is 122303101463. The reversal of 122303101433 is 334101303221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 80845254889 + 41457846544 = 284333^2 + 203612^2 .

It is a cyclic number.

It is not a de Polignac number, because 122303101433 - 26 = 122303101369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 122303101399 and 122303101408.

It is not a weakly prime, because it can be changed into another prime (122303101463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61151550716 + 61151550717.

It is an arithmetic number, because the mean of its divisors is an integer number (61151550717).

Almost surely, 2122303101433 is an apocalyptic number.

It is an amenable number.

122303101433 is a deficient number, since it is larger than the sum of its proper divisors (1).

122303101433 is an equidigital number, since it uses as much as digits as its factorization.

122303101433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 122303101433 its reverse (334101303221), we get a palindrome (456404404654).

The spelling of 122303101433 in words is "one hundred twenty-two billion, three hundred three million, one hundred one thousand, four hundred thirty-three".