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12231300113 = 411631830211
BaseRepresentation
bin10110110010000101…
…01101010000010001
31011120102100102110022
423121002231100101
5200022203100423
65341411113225
7612050223044
oct133102552021
934512312408
1012231300113
11520728289a
1224542a2815
1311cc05a7b6
1484062ac5b
154b8c0ddc8
hex2d90ad411

12231300113 has 8 divisors (see below), whose sum is σ = 12606500256. Its totient is φ = 11859760800.

The previous prime is 12231300071. The next prime is 12231300119. The reversal of 12231300113 is 31100313221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12231300113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12231300091 and 12231300100.

It is not an unprimeable number, because it can be changed into a prime (12231300119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 908423 + ... + 921788.

It is an arithmetic number, because the mean of its divisors is an integer number (1575812532).

Almost surely, 212231300113 is an apocalyptic number.

It is an amenable number.

12231300113 is a deficient number, since it is larger than the sum of its proper divisors (375200143).

12231300113 is a wasteful number, since it uses less digits than its factorization.

12231300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1830415.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 12231300113 its reverse (31100313221), we get a palindrome (43331613334).

The spelling of 12231300113 in words is "twelve billion, two hundred thirty-one million, three hundred thousand, one hundred thirteen".

Divisors: 1 41 163 6683 1830211 75038651 298324393 12231300113