Base | Representation |
---|---|
bin | 10001110011001000010… |
… | …000101000100000101111 |
3 | 11022221010001212001011211 |
4 | 101303020100220200233 |
5 | 130014432402444003 |
6 | 2333522015455251 |
7 | 154240212561211 |
oct | 21631020504057 |
9 | 4287101761154 |
10 | 1223130515503 |
11 | 4317aa31a806 |
12 | 179073b27527 |
13 | 8b457713180 |
14 | 432b24ac5b1 |
15 | 21c3a6cb96d |
hex | 11cc842882f |
1223130515503 has 16 divisors (see below), whose sum is σ = 1325927322720. Its totient is φ = 1121600369664.
The previous prime is 1223130515443. The next prime is 1223130515527. The reversal of 1223130515503 is 3055150313221.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1223130515503 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1223130515903) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 845268 + ... + 1777846.
It is an arithmetic number, because the mean of its divisors is an integer number (82870457670).
Almost surely, 21223130515503 is an apocalyptic number.
1223130515503 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1223130515503 is a deficient number, since it is larger than the sum of its proper divisors (102796807217).
1223130515503 is a wasteful number, since it uses less digits than its factorization.
1223130515503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 933258.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 1223130515503 its reverse (3055150313221), we get a palindrome (4278280828724).
The spelling of 1223130515503 in words is "one trillion, two hundred twenty-three billion, one hundred thirty million, five hundred fifteen thousand, five hundred three".
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