Base | Representation |
---|---|
bin | 11011110011111001000011… |
… | …101000011000100000011111 |
3 | 121001002000210010201212102111 |
4 | 123303321003220120200133 |
5 | 112012434430102040403 |
6 | 1112045525310134451 |
7 | 34522560310014256 |
oct | 3363710350304037 |
9 | 531060703655374 |
10 | 122313213315103 |
11 | 35a77819243518 |
12 | 118751537b1427 |
13 | 533311812b395 |
14 | 222bdc387779d |
15 | e219a9d2d56d |
hex | 6f3e43a1881f |
122313213315103 has 2 divisors, whose sum is σ = 122313213315104. Its totient is φ = 122313213315102.
The previous prime is 122313213315091. The next prime is 122313213315109. The reversal of 122313213315103 is 301513312313221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122313213315103 - 237 = 122175774361631 is a prime.
It is a super-2 number, since 2×1223132133151032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122313213315109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61156606657551 + 61156606657552.
It is an arithmetic number, because the mean of its divisors is an integer number (61156606657552).
Almost surely, 2122313213315103 is an apocalyptic number.
122313213315103 is a deficient number, since it is larger than the sum of its proper divisors (1).
122313213315103 is an equidigital number, since it uses as much as digits as its factorization.
122313213315103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 122313213315103 its reverse (301513312313221), we get a palindrome (423826525628324).
The spelling of 122313213315103 in words is "one hundred twenty-two trillion, three hundred thirteen billion, two hundred thirteen million, three hundred fifteen thousand, one hundred three".
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