Base | Representation |
---|---|
bin | 111000111101010000… |
… | …0000100100110000011 |
3 | 102200201021221211211012 |
4 | 1301322200010212003 |
5 | 4000444430441232 |
6 | 132105044111135 |
7 | 11560030332623 |
oct | 1617240044603 |
9 | 380637854735 |
10 | 122314312067 |
11 | 47967271022 |
12 | 1b8569954ab |
13 | b6c38009ac |
14 | 5cc485c883 |
15 | 32ad2529b2 |
hex | 1c7a804983 |
122314312067 has 2 divisors, whose sum is σ = 122314312068. Its totient is φ = 122314312066.
The previous prime is 122314312063. The next prime is 122314312069. The reversal of 122314312067 is 760213413221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122314312067 - 22 = 122314312063 is a prime.
It is a super-3 number, since 3×1223143120673 (a number of 34 digits) contains 333 as substring.
Together with 122314312069, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (122314312063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61157156033 + 61157156034.
It is an arithmetic number, because the mean of its divisors is an integer number (61157156034).
Almost surely, 2122314312067 is an apocalyptic number.
122314312067 is a deficient number, since it is larger than the sum of its proper divisors (1).
122314312067 is an equidigital number, since it uses as much as digits as its factorization.
122314312067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 122314312067 its reverse (760213413221), we get a palindrome (882527725288).
The spelling of 122314312067 in words is "one hundred twenty-two billion, three hundred fourteen million, three hundred twelve thousand, sixty-seven".
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