1223201104341 has 4 divisors (see below), whose sum is σ = 1630934805792. Its totient is φ = 815467402892.

The previous prime is 1223201104297. The next prime is 1223201104343. The reversal of 1223201104341 is 1434011023221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1223201104341 is a prime.

It is a super-2 number, since 2×1223201104341² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1223201104343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203866850721 + ... + 203866850726.

It is an arithmetic number, because the mean of its divisors is an integer number (407733701448).

Almost surely, 2^{1223201104341} is an apocalyptic number.

It is an amenable number.

1223201104341 is a deficient number, since it is larger than the sum of its proper divisors (407733701451).

1223201104341 is an equidigital number, since it uses as much as digits as its factorization.

1223201104341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 407733701450.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1223201104341 its reverse (1434011023221), we get a palindrome (2657212127562).

The spelling of 1223201104341 in words is "one trillion, two hundred twenty-three billion, two hundred one million, one hundred four thousand, three hundred forty-one".