Base | Representation |
---|---|
bin | 10001110011001100100… |
… | …110010010101001011101 |
3 | 11022221022010210222110022 |
4 | 101303030212102221131 |
5 | 130020110021130411 |
6 | 2333533135521525 |
7 | 154242055341533 |
oct | 21631446225135 |
9 | 4287263728408 |
10 | 1223203301981 |
11 | 431837414321 |
12 | 1790943892a5 |
13 | 8b4698190ab |
14 | 432bc018153 |
15 | 21c41ca7edb |
hex | 11ccc992a5d |
1223203301981 has 2 divisors, whose sum is σ = 1223203301982. Its totient is φ = 1223203301980.
The previous prime is 1223203301959. The next prime is 1223203302031. The reversal of 1223203301981 is 1891033023221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1148733804100 + 74469497881 = 1071790^2 + 272891^2 .
It is an emirp because it is prime and its reverse (1891033023221) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1223203301981 is a prime.
It is a super-2 number, since 2×12232033019812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1223203301921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611601650990 + 611601650991.
It is an arithmetic number, because the mean of its divisors is an integer number (611601650991).
Almost surely, 21223203301981 is an apocalyptic number.
It is an amenable number.
1223203301981 is a deficient number, since it is larger than the sum of its proper divisors (1).
1223203301981 is an equidigital number, since it uses as much as digits as its factorization.
1223203301981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 1223203301981 in words is "one trillion, two hundred twenty-three billion, two hundred three million, three hundred one thousand, nine hundred eighty-one".
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