Base | Representation |
---|---|
bin | 11011110100000100000100… |
… | …100111100100110010101011 |
3 | 121001010011022102200120112010 |
4 | 123310010010213210302223 |
5 | 112013133141001244210 |
6 | 1112055203103251003 |
7 | 34523456360016663 |
oct | 3364040447446253 |
9 | 531104272616463 |
10 | 122325041040555 |
11 | 35a81838729731 |
12 | 118774b48a9a63 |
13 | 53342816954b2 |
14 | 222c7c664d1a3 |
15 | e21e4d3be920 |
hex | 6f41049e4cab |
122325041040555 has 64 divisors (see below), whose sum is σ = 201628538496000. Its totient is φ = 63288595937280.
The previous prime is 122325041040547. The next prime is 122325041040557. The reversal of 122325041040555 is 555040140523221.
It is not a de Polignac number, because 122325041040555 - 23 = 122325041040547 is a prime.
It is not an unprimeable number, because it can be changed into a prime (122325041040557) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1917318546 + ... + 1917382344.
It is an arithmetic number, because the mean of its divisors is an integer number (3150445914000).
Almost surely, 2122325041040555 is an apocalyptic number.
122325041040555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
122325041040555 is a deficient number, since it is larger than the sum of its proper divisors (79303497455445).
122325041040555 is a wasteful number, since it uses less digits than its factorization.
122325041040555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81444.
The product of its (nonzero) digits is 240000, while the sum is 39.
Adding to 122325041040555 its reverse (555040140523221), we get a palindrome (677365181563776).
The spelling of 122325041040555 in words is "one hundred twenty-two trillion, three hundred twenty-five billion, forty-one million, forty thousand, five hundred fifty-five".
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