Base | Representation |
---|---|
bin | 10110110010010010… |
… | …01100010010111001 |
3 | 1011120112112210102120 |
4 | 23121021030102321 |
5 | 200023122000441 |
6 | 5341511351453 |
7 | 612100533246 |
oct | 133111142271 |
9 | 34515483376 |
10 | 12233000121 |
11 | 5208234061 |
12 | 2454982589 |
13 | 11cc504514 |
14 | 8409505cd |
15 | 4b8e47966 |
hex | 2d924c4b9 |
12233000121 has 4 divisors (see below), whose sum is σ = 16310666832. Its totient is φ = 8155333412.
The previous prime is 12233000099. The next prime is 12233000123. The reversal of 12233000121 is 12100033221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12233000121 - 213 = 12232991929 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12233000121.
It is not an unprimeable number, because it can be changed into a prime (12233000123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2038833351 + ... + 2038833356.
It is an arithmetic number, because the mean of its divisors is an integer number (4077666708).
Almost surely, 212233000121 is an apocalyptic number.
It is an amenable number.
12233000121 is a deficient number, since it is larger than the sum of its proper divisors (4077666711).
12233000121 is an equidigital number, since it uses as much as digits as its factorization.
12233000121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4077666710.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 12233000121 its reverse (12100033221), we get a palindrome (24333033342).
The spelling of 12233000121 in words is "twelve billion, two hundred thirty-three million, one hundred twenty-one", and thus it is an aban number.
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