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122330041441493 is a prime number
BaseRepresentation
bin11011110100001000101110…
…101010100101110011010101
3121001010122012220211021001212
4123310020232222211303111
5112013223411102111433
61112101351211231205
734524024315514244
oct3364105652456325
9531118186737055
10122330041441493
1135a8397428a996
121187846b448505
13533489a634712
14222cb3c7b695b
15e221423a4d48
hex6f422eaa5cd5

122330041441493 has 2 divisors, whose sum is σ = 122330041441494. Its totient is φ = 122330041441492.

The previous prime is 122330041441403. The next prime is 122330041441501. The reversal of 122330041441493 is 394144140033221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121026247423249 + 1303794018244 = 11001193^2 + 1141838^2 .

It is a cyclic number.

It is not a de Polignac number, because 122330041441493 - 230 = 122328967699669 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 122330041441493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122330041441403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61165020720746 + 61165020720747.

It is an arithmetic number, because the mean of its divisors is an integer number (61165020720747).

Almost surely, 2122330041441493 is an apocalyptic number.

It is an amenable number.

122330041441493 is a deficient number, since it is larger than the sum of its proper divisors (1).

122330041441493 is an equidigital number, since it uses as much as digits as its factorization.

122330041441493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 248832, while the sum is 41.

The spelling of 122330041441493 in words is "one hundred twenty-two trillion, three hundred thirty billion, forty-one million, four hundred forty-one thousand, four hundred ninety-three".