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1223312031133 is a prime number
BaseRepresentation
bin10001110011010011000…
…101000011110110011101
311022221120201101222210221
4101303103011003312131
5130020320334444013
62333552022201341
7154244545461253
oct21632305036635
94287521358727
101223312031133
11431892828125
12179104883251
138b4861c7b7a
14432cc63c5d3
1521c4b5d408d
hex11cd3143d9d

1223312031133 has 2 divisors, whose sum is σ = 1223312031134. Its totient is φ = 1223312031132.

The previous prime is 1223312031127. The next prime is 1223312031217. The reversal of 1223312031133 is 3311302133221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1108013074884 + 115298956249 = 1052622^2 + 339557^2 .

It is a cyclic number.

It is not a de Polignac number, because 1223312031133 - 221 = 1223309933981 is a prime.

It is a super-2 number, since 2×12233120311332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1223312031098 and 1223312031107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1223312031103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611656015566 + 611656015567.

It is an arithmetic number, because the mean of its divisors is an integer number (611656015567).

Almost surely, 21223312031133 is an apocalyptic number.

It is an amenable number.

1223312031133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1223312031133 is an equidigital number, since it uses as much as digits as its factorization.

1223312031133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1223312031133 its reverse (3311302133221), we get a palindrome (4534614164354).

The spelling of 1223312031133 in words is "one trillion, two hundred twenty-three billion, three hundred twelve million, thirty-one thousand, one hundred thirty-three".