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12233211000000 = 2635641271367
BaseRepresentation
bin1011001000000100010000…
…1100100011010011000000
31121022111001111201101120220
42302001010030203103000
53100412104004000000
642003505355103040
72401551241551264
oct262010414432300
947274044641526
1012233211000000
113997091765941
121456a65741a80
136a97823c4443
1430413a7580a4
15163331d411a0
hexb20443234c0

12233211000000 has 784 divisors, whose sum is σ = 41711346087936. Its totient is φ = 3162240000000.

The previous prime is 12233210999941. The next prime is 12233211000067. The reversal of 12233211000000 is 11233221.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 33332999817 + ... + 33333000183.

Almost surely, 212233211000000 is an apocalyptic number.

12233211000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12233211000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20855673043968).

12233211000000 is an abundant number, since it is smaller than the sum of its proper divisors (29478135087936).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12233211000000 is an frugal number, since it uses more digits than its factorization.

12233211000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 724 (or 689 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 12233211000000 its reverse (11233221), we get a palindrome (12233222233221).

The spelling of 12233211000000 in words is "twelve trillion, two hundred thirty-three billion, two hundred eleven million", and thus it is an aban number.