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12234132641543 is a prime number
BaseRepresentation
bin1011001000000111101100…
…1000010101011100000111
31121022120102201221122002212
42302001323020111130013
53100421000424012133
642004141041054035
72401613132434001
oct262017310253407
947276381848085
1012234132641543
113997514a2986a
12145708232731b
136a989b327477
143041c6d09371
15163387be5148
hexb207b215707

12234132641543 has 2 divisors, whose sum is σ = 12234132641544. Its totient is φ = 12234132641542.

The previous prime is 12234132641513. The next prime is 12234132641551. The reversal of 12234132641543 is 34514623143221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12234132641543 - 216 = 12234132576007 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12234132641543.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12234132641513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6117066320771 + 6117066320772.

It is an arithmetic number, because the mean of its divisors is an integer number (6117066320772).

Almost surely, 212234132641543 is an apocalyptic number.

12234132641543 is a deficient number, since it is larger than the sum of its proper divisors (1).

12234132641543 is an equidigital number, since it uses as much as digits as its factorization.

12234132641543 is an evil number, because the sum of its binary digits is even.

The product of its digits is 414720, while the sum is 41.

Adding to 12234132641543 its reverse (34514623143221), we get a palindrome (46748755784764).

The spelling of 12234132641543 in words is "twelve trillion, two hundred thirty-four billion, one hundred thirty-two million, six hundred forty-one thousand, five hundred forty-three".