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122343020555047 is a prime number
BaseRepresentation
bin11011110100010100110100…
…010001111110101100100111
3121001011212201110022112201021
4123310110310101332230213
5112013432001230230142
61112111335134512011
734524664046251405
oct3364246421765447
9531155643275637
10122343020555047
1135a8942469a016
121187aa92065607
135335b885a2676
14222d610466475
15e22651a7d267
hex6f453447eb27

122343020555047 has 2 divisors, whose sum is σ = 122343020555048. Its totient is φ = 122343020555046.

The previous prime is 122343020554999. The next prime is 122343020555081. The reversal of 122343020555047 is 740555020343221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 122343020555047 - 211 = 122343020552999 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 122343020554994 and 122343020555012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122343020555087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61171510277523 + 61171510277524.

It is an arithmetic number, because the mean of its divisors is an integer number (61171510277524).

Almost surely, 2122343020555047 is an apocalyptic number.

122343020555047 is a deficient number, since it is larger than the sum of its proper divisors (1).

122343020555047 is an equidigital number, since it uses as much as digits as its factorization.

122343020555047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008000, while the sum is 43.

Adding to 122343020555047 its reverse (740555020343221), we get a palindrome (862898040898268).

The spelling of 122343020555047 in words is "one hundred twenty-two trillion, three hundred forty-three billion, twenty million, five hundred fifty-five thousand, forty-seven".