Search a number
-
+
12234356003497 is a prime number
BaseRepresentation
bin1011001000001000100001…
…1100011001001010101001
31121022121000022020121002211
42302002020130121022221
53100421430114102442
642004215140325121
72401621514122015
oct262021034311251
947277008217084
1012234356003497
11399761a018a21
1214571250a37a1
136a99056a11c4
1430420884d545
1516339c616617
hexb20887192a9

12234356003497 has 2 divisors, whose sum is σ = 12234356003498. Its totient is φ = 12234356003496.

The previous prime is 12234356003489. The next prime is 12234356003593. The reversal of 12234356003497 is 79430065343221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12159036494361 + 75319509136 = 3486981^2 + 274444^2 .

It is a cyclic number.

It is not a de Polignac number, because 12234356003497 - 23 = 12234356003489 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12234356003497.

It is not a weakly prime, because it can be changed into another prime (12234356003437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6117178001748 + 6117178001749.

It is an arithmetic number, because the mean of its divisors is an integer number (6117178001749).

Almost surely, 212234356003497 is an apocalyptic number.

It is an amenable number.

12234356003497 is a deficient number, since it is larger than the sum of its proper divisors (1).

12234356003497 is an equidigital number, since it uses as much as digits as its factorization.

12234356003497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3265920, while the sum is 49.

The spelling of 12234356003497 in words is "twelve trillion, two hundred thirty-four billion, three hundred fifty-six million, three thousand, four hundred ninety-seven".