Base | Representation |
---|---|
bin | 10001110011100000101… |
… | …101011111010110011111 |
3 | 11022222011122202021021011 |
4 | 101303200231133112133 |
5 | 130021302411431333 |
6 | 2334030432120051 |
7 | 154253323430455 |
oct | 21634055372637 |
9 | 4288148667234 |
10 | 1223540733343 |
11 | 43199a934515 |
12 | 179169396027 |
13 | 8b4c16c1516 |
14 | 43310b729d5 |
15 | 21c6170c9cd |
hex | 11ce0b5f59f |
1223540733343 has 2 divisors, whose sum is σ = 1223540733344. Its totient is φ = 1223540733342.
The previous prime is 1223540733323. The next prime is 1223540733379. The reversal of 1223540733343 is 3433370453221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1223540733343 - 29 = 1223540732831 is a prime.
It is a super-2 number, since 2×12235407333432 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1223540733296 and 1223540733305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1223540733323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611770366671 + 611770366672.
It is an arithmetic number, because the mean of its divisors is an integer number (611770366672).
Almost surely, 21223540733343 is an apocalyptic number.
1223540733343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1223540733343 is an equidigital number, since it uses as much as digits as its factorization.
1223540733343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 40.
The spelling of 1223540733343 in words is "one trillion, two hundred twenty-three billion, five hundred forty million, seven hundred thirty-three thousand, three hundred forty-three".
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