Base | Representation |
---|---|
bin | 111000111110110011… |
… | …0100011101101111001 |
3 | 102200211220212100021221 |
4 | 1301331212203231321 |
5 | 4001101241002212 |
6 | 132114143232041 |
7 | 11561231522446 |
oct | 1617546435571 |
9 | 380756770257 |
10 | 122366344057 |
11 | 4799367a471 |
12 | 1b8702a8621 |
13 | b70151ac59 |
14 | 5ccb7249cd |
15 | 32b2ace807 |
hex | 1c7d9a3b79 |
122366344057 has 4 divisors (see below), whose sum is σ = 125350889076. Its totient is φ = 119381799040.
The previous prime is 122366344039. The next prime is 122366344069. The reversal of 122366344057 is 750443663221.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10130623801 + 112235720256 = 100651^2 + 335016^2 .
It is a cyclic number.
It is not a de Polignac number, because 122366344057 - 211 = 122366342009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (122366344007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1492272448 + ... + 1492272529.
It is an arithmetic number, because the mean of its divisors is an integer number (31337722269).
Almost surely, 2122366344057 is an apocalyptic number.
It is an amenable number.
122366344057 is a deficient number, since it is larger than the sum of its proper divisors (2984545019).
122366344057 is an equidigital number, since it uses as much as digits as its factorization.
122366344057 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2984545018.
The product of its (nonzero) digits is 725760, while the sum is 43.
The spelling of 122366344057 in words is "one hundred twenty-two billion, three hundred sixty-six million, three hundred forty-four thousand, fifty-seven".
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