122402140511413 has 4 divisors (see below), whose sum is σ = 139888160584480. Its totient is φ = 104916120438348.

The previous prime is 122402140511411. The next prime is 122402140511437. The reversal of 122402140511413 is 314115041204221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 122402140511413 - 2¹ = 122402140511411 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122402140511411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8743010036523 + ... + 8743010036536.

It is an arithmetic number, because the mean of its divisors is an integer number (34972040146120).

Almost surely, 2^{122402140511413} is an apocalyptic number.

It is an amenable number.

122402140511413 is a deficient number, since it is larger than the sum of its proper divisors (17486020073067).

122402140511413 is an equidigital number, since it uses as much as digits as its factorization.

122402140511413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17486020073066.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 122402140511413 its reverse (314115041204221), we get a palindrome (436517181715634).

The spelling of 122402140511413 in words is "one hundred twenty-two trillion, four hundred two billion, one hundred forty million, five hundred eleven thousand, four hundred thirteen".