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122404025255143 is a prime number
BaseRepresentation
bin11011110101001101101000…
…011100011100010011100111
3121001101201011222102101220011
4123311031220130130103213
5112020431420431131033
61112155344413151051
734532253565534042
oct3365155034342347
9531351158371804
10122404025255143
113600228a210135
121188a87848b487
13533b85b224148
14223255a52bc59
15e240225deccd
hex6f536871c4e7

122404025255143 has 2 divisors, whose sum is σ = 122404025255144. Its totient is φ = 122404025255142.

The previous prime is 122404025255137. The next prime is 122404025255153. The reversal of 122404025255143 is 341552520404221.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 122404025255143 - 221 = 122404023157991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 122404025255096 and 122404025255105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122404025255153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61202012627571 + 61202012627572.

It is an arithmetic number, because the mean of its divisors is an integer number (61202012627572).

Almost surely, 2122404025255143 is an apocalyptic number.

122404025255143 is a deficient number, since it is larger than the sum of its proper divisors (1).

122404025255143 is an equidigital number, since it uses as much as digits as its factorization.

122404025255143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384000, while the sum is 40.

Adding to 122404025255143 its reverse (341552520404221), we get a palindrome (463956545659364).

The spelling of 122404025255143 in words is "one hundred twenty-two trillion, four hundred four billion, twenty-five million, two hundred fifty-five thousand, one hundred forty-three".