Base | Representation |
---|---|
bin | 10001110100000010100… |
… | …010101001110110100001 |
3 | 11100000122012202120012022 |
4 | 101310002202221312201 |
5 | 130023433212134423 |
6 | 2334203025311225 |
7 | 154303355011532 |
oct | 21640242516641 |
9 | 4300565676168 |
10 | 1224108318113 |
11 | 43216126233a |
12 | 1792a7495515 |
13 | 8b58217a9b5 |
14 | 433662bc689 |
15 | 21c96475dc8 |
hex | 11d028a9da1 |
1224108318113 has 2 divisors, whose sum is σ = 1224108318114. Its totient is φ = 1224108318112.
The previous prime is 1224108318091. The next prime is 1224108318161. The reversal of 1224108318113 is 3118138014221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 753550733329 + 470557584784 = 868073^2 + 685972^2 .
It is a cyclic number.
It is not a de Polignac number, because 1224108318113 - 220 = 1224107269537 is a prime.
It is not a weakly prime, because it can be changed into another prime (1224108318413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612054159056 + 612054159057.
It is an arithmetic number, because the mean of its divisors is an integer number (612054159057).
Almost surely, 21224108318113 is an apocalyptic number.
It is an amenable number.
1224108318113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1224108318113 is an equidigital number, since it uses as much as digits as its factorization.
1224108318113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 35.
The spelling of 1224108318113 in words is "one trillion, two hundred twenty-four billion, one hundred eight million, three hundred eighteen thousand, one hundred thirteen".
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