1224114100121 has 4 divisors (see below), whose sum is σ = 1335397200144. Its totient is φ = 1112831000100.

The previous prime is 1224114100087. The next prime is 1224114100193. The reversal of 1224114100121 is 1210014114221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1224114100121 - 2³⁰ = 1223040358297 is a prime.

It is a super-2 number, since 2×1224114100121² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1224114100093 and 1224114100102.

It is not an unprimeable number, because it can be changed into a prime (1224114100621) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55641549995 + ... + 55641550016.

It is an arithmetic number, because the mean of its divisors is an integer number (333849300036).

Almost surely, 2^{1224114100121} is an apocalyptic number.

1224114100121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1224114100121 is a deficient number, since it is larger than the sum of its proper divisors (111283100023).

1224114100121 is a wasteful number, since it uses less digits than its factorization.

1224114100121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111283100022.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 1224114100121 its reverse (1210014114221), we get a palindrome (2434128214342).

It can be divided in two parts, 1224114100 and 121, that added together give a palindrome (1224114221).

The spelling of 1224114100121 in words is "one trillion, two hundred twenty-four billion, one hundred fourteen million, one hundred thousand, one hundred twenty-one".