Base | Representation |
---|---|
bin | 10001110100000010111… |
… | …010000000011110110010 |
3 | 11100000122122021121000002 |
4 | 101310002322000132302 |
5 | 130023441244040424 |
6 | 2334203404430002 |
7 | 154303461030116 |
oct | 21640272003662 |
9 | 4300578247002 |
10 | 1224114440114 |
11 | 432164763945 |
12 | 1792a9548302 |
13 | 8b583512397 |
14 | 43367033746 |
15 | 21c96c84cae |
hex | 11d02e807b2 |
1224114440114 has 4 divisors (see below), whose sum is σ = 1836171660174. Its totient is φ = 612057220056.
The previous prime is 1224114440113. The next prime is 1224114440189. The reversal of 1224114440114 is 4110444114221.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 698804043025 + 525310397089 = 835945^2 + 724783^2 .
It is a super-2 number, since 2×12241144401142 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1224114440113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 306028610027 + ... + 306028610030.
Almost surely, 21224114440114 is an apocalyptic number.
1224114440114 is a deficient number, since it is larger than the sum of its proper divisors (612057220060).
1224114440114 is an equidigital number, since it uses as much as digits as its factorization.
1224114440114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 612057220059.
The product of its (nonzero) digits is 4096, while the sum is 29.
Adding to 1224114440114 its reverse (4110444114221), we get a palindrome (5334558554335).
The spelling of 1224114440114 in words is "one trillion, two hundred twenty-four billion, one hundred fourteen million, four hundred forty thousand, one hundred fourteen".
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