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12241314001 = 71748759143
BaseRepresentation
bin10110110011010001…
…11010000011010001
31011121010012011221001
423121220322003101
5200032234022001
65342405502001
7612231311050
oct133150720321
934533164831
1012241314001
1152119a2434
122457711901
131201155787
14841ab6397
154b9a3b001
hex2d9a3a0d1

12241314001 has 4 divisors (see below), whose sum is σ = 13990073152. Its totient is φ = 10492554852.

The previous prime is 12241313999. The next prime is 12241314011. The reversal of 12241314001 is 10041314221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12241314001 - 21 = 12241313999 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12241314001.

It is not an unprimeable number, because it can be changed into a prime (12241314011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 874379565 + ... + 874379578.

It is an arithmetic number, because the mean of its divisors is an integer number (3497518288).

Almost surely, 212241314001 is an apocalyptic number.

It is an amenable number.

12241314001 is a deficient number, since it is larger than the sum of its proper divisors (1748759151).

12241314001 is an equidigital number, since it uses as much as digits as its factorization.

12241314001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1748759150.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 12241314001 its reverse (10041314221), we get a palindrome (22282628222).

The spelling of 12241314001 in words is "twelve billion, two hundred forty-one million, three hundred fourteen thousand, one".

Divisors: 1 7 1748759143 12241314001