Base | Representation |
---|---|
bin | 100110110111110000000… |
… | …1011101010010000110001 |
3 | 200220201200102110212001111 |
4 | 1031233200023222100301 |
5 | 1200012221302031001 |
6 | 15210133414433321 |
7 | 1060655534335621 |
oct | 115574013522061 |
9 | 20821612425044 |
10 | 5342405502001 |
11 | 177a7796a2087 |
12 | 723488962841 |
13 | 2c9a2c439499 |
14 | 146806748881 |
15 | 93e7cb78851 |
hex | 4dbe02ea431 |
5342405502001 has 4 divisors (see below), whose sum is σ = 5574684002112. Its totient is φ = 5110127001892.
The previous prime is 5342405501999. The next prime is 5342405502011. The reversal of 5342405502001 is 1002055042435.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5342405502001 - 21 = 5342405501999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5342405502011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116139250021 + ... + 116139250066.
It is an arithmetic number, because the mean of its divisors is an integer number (1393671000528).
Almost surely, 25342405502001 is an apocalyptic number.
It is an amenable number.
5342405502001 is a deficient number, since it is larger than the sum of its proper divisors (232278500111).
5342405502001 is a wasteful number, since it uses less digits than its factorization.
5342405502001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 232278500110.
The product of its (nonzero) digits is 24000, while the sum is 31.
The spelling of 5342405502001 in words is "five trillion, three hundred forty-two billion, four hundred five million, five hundred two thousand, one".
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