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122413439 is a prime number
BaseRepresentation
bin1110100101111…
…10000101111111
322112100020200002
413102332011333
5222314212224
620051424515
73014332331
oct722760577
9275306602
10122413439
1163110035
1234bb513b
131c4905b5
1412387451
15ab309ae
hex74be17f

122413439 has 2 divisors, whose sum is σ = 122413440. Its totient is φ = 122413438.

The previous prime is 122413433. The next prime is 122413471. The reversal of 122413439 is 934314221.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122413439 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122413433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61206719 + 61206720.

It is an arithmetic number, because the mean of its divisors is an integer number (61206720).

Almost surely, 2122413439 is an apocalyptic number.

122413439 is a deficient number, since it is larger than the sum of its proper divisors (1).

122413439 is an equidigital number, since it uses as much as digits as its factorization.

122413439 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5184, while the sum is 29.

The square root of 122413439 is about 11064.0606921690. The cubic root of 122413439 is about 496.5271869843.

The spelling of 122413439 in words is "one hundred twenty-two million, four hundred thirteen thousand, four hundred thirty-nine".