Base | Representation |
---|---|
bin | 10110110011010010… |
… | …10110011111001001 |
3 | 1011121010102002200211 |
4 | 23121221112133021 |
5 | 200032301233343 |
6 | 5342412201121 |
7 | 612232304446 |
oct | 133151263711 |
9 | 34533362624 |
10 | 12241430473 |
11 | 5211a71998 |
12 | 24577691a1 |
13 | 12011967ac |
14 | 841b069cd |
15 | 4b9a6079d |
hex | 2d9a567c9 |
12241430473 has 2 divisors, whose sum is σ = 12241430474. Its totient is φ = 12241430472.
The previous prime is 12241430441. The next prime is 12241430483. The reversal of 12241430473 is 37403414221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7812261769 + 4429168704 = 88387^2 + 66552^2 .
It is a cyclic number.
It is not a de Polignac number, because 12241430473 - 25 = 12241430441 is a prime.
It is not a weakly prime, because it can be changed into another prime (12241430413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6120715236 + 6120715237.
It is an arithmetic number, because the mean of its divisors is an integer number (6120715237).
Almost surely, 212241430473 is an apocalyptic number.
It is an amenable number.
12241430473 is a deficient number, since it is larger than the sum of its proper divisors (1).
12241430473 is an equidigital number, since it uses as much as digits as its factorization.
12241430473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 12241430473 its reverse (37403414221), we get a palindrome (49644844694).
The spelling of 12241430473 in words is "twelve billion, two hundred forty-one million, four hundred thirty thousand, four hundred seventy-three".
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